How do you bypass a bank angle sensor on a twin cam
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As mentioned in the other thread, I believe it is a 5 volt signal. If you want to try to bypass it, you will need a 5 volt power source. Building such and item will likely be larger than the BAS. It will also need to be built to withstand the adverse conditions associated with being on a motorcycle. Hate to sound like a broken record but the BAS is already built to these standards and will be reliable. It would be very easy to mount the small BAS near the ignition module and have minimal amounts of wires to run.
If you still want to build something that supply the signal, I would suggest using a LM7805 voltage regulator. You will also need a current limiting resister on the output. A 100k 1/4 watt resister should work. You will need to make 3 connections to the device, ground, 12 volts and signal to the ignition module. BTW, they are the same connections you would make to a BAS.
Here is a bike build that I did exactly what I am suggesting. https://www.hdforums.com/m_242003/tm.htm
Here is a picture of the wiring when completed. The BAS is located on the back of the battery box. You can see the gray connector of the BAS right beside the red tab on the frame (right side). Note its location compared to the ignition module, about 1 inch above the gray connector on the ignition module.
Been there a long time ago and wired a doide in place of a sensor. Was years back so without digging through all the notes, can't remember specs. It worked because of the way the circuit is laid out. Thanks for the lecture on why it won't work, but it does.
Have a Great day.
The bank angle takes a high voltage and cuts it down to a low voltage - the ignition coil uses a low voltage as a signal to operate - not tipped. When the sensor is activated, voltage goes higher and that is the signal not to operate. Some guys have used resistors - if you look at the wiring, you can make a bypass with a diode.
The suggestion above, as I read it, is the signal to disable the ignition is a "hi" or 5 volts. And the signal that enables the ignition is a "Lo" or ground. If this is a the case, and I have not confirmed it, then pulling the signal for enable Lo would then turn on the ignition.
To confirm the ignition is enabled when the "ignition enable" pin is Lo, turn the bike on and check the voltage on the pin. If it reads 5 volts with nothing attached, then a Lo signal will probably enable it.
To do this a resister could be used. The resister value could vary considerably depending on the circuit in the ignition module. IMO, the highest resister value that pulls it Lo should be used. To test this, go to radio shack and buy an assortment of resisters. I would recommend 100K Ohm 1/4 watt, 10K Ohm 1/4 watt, 5K Ohm 1/4 watt and 1K Ohm 1/4 watt resisters. Starting with the highest value (100K), connect one end to the ignition enable pin on the ignition module (black connector, pin 10 I believe). Then connect the other end of the resister to ground. When you turn the bike on (run position) the signal at pin 10 should read zero volts (ground). If it does not then use the next lower value resister until it read 0 volts on the pin. Remember the resister is used to limit the amount of current draw on that signal so the higher the value, the less current draw.
Good luck and let us know if it works and what value resister you used.
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I don't necessarily need to bypass the BAS ... though I wouldn't mind doing so.
although resistors do resist current, they do have a voltage drop across them, often, used in a comparator circuit.






