turn signal canceller not blinking
#1
turn signal canceller not blinking
My 96 sportster recently had installed some led turn signals. My problem is that when actuated the turn signals come on solid. But when the hazard is on. they blink fine. I have read many posts and how led lights need some load something. Why would it work with the hazard? My wiring is fine and so are voltages and ground. Pleass help
#2
Hey Chief try this
This may solve your problem.http://www.kuryakyn.com/Products/757...Load-Equalizer
Ex Navy Scope Dope here.
Ex Navy Scope Dope here.
#4
so can I overcome this by installing a resistor inline. next concern is how much resistance?
my issue is that I spent 40 dollars and to spend another 40 for two load balancers does not make sense.
I was thinking of going super cheap and installing a regular old-style flasher for each side but I do not know if it will hurt the canceller.
thanks
my issue is that I spent 40 dollars and to spend another 40 for two load balancers does not make sense.
I was thinking of going super cheap and installing a regular old-style flasher for each side but I do not know if it will hurt the canceller.
thanks
#5
#6
Join Date: Oct 2012
Location: In the foothills of southwestern NC - US of A
Posts: 1,358
Likes: 0
Received 22 Likes
on
19 Posts
Yesh, Ohms Law:
voltage ÷ current = resistance
For example, if your standard bulbs are 12 volts and draw 2 amps then each bulbs resistance value is 6 ohms (12 ÷ 2 = 6).
Or if they were 12 volt and drew 3.7 amps of current the resistance value of each would be 3.24 ohms (12 ÷ 3.7 = 3.24 (ohms)).
So, if you can use Ohms Law to figure out the resistance value of your standard bulbs you can use Ohms Law to figure out the resistance of the new LED bulbs. You then simply take the standard bulb resistance value and subtract from that the resistance value of the new LEDs, and the resulting number will be the value of resistance that you need to add to each LED bulb for them to operate properly.
=8^)
voltage ÷ current = resistance
For example, if your standard bulbs are 12 volts and draw 2 amps then each bulbs resistance value is 6 ohms (12 ÷ 2 = 6).
Or if they were 12 volt and drew 3.7 amps of current the resistance value of each would be 3.24 ohms (12 ÷ 3.7 = 3.24 (ohms)).
So, if you can use Ohms Law to figure out the resistance value of your standard bulbs you can use Ohms Law to figure out the resistance of the new LED bulbs. You then simply take the standard bulb resistance value and subtract from that the resistance value of the new LEDs, and the resulting number will be the value of resistance that you need to add to each LED bulb for them to operate properly.
=8^)
#7
Yesh, Ohms Law:
voltage ÷ current = resistance
For example, if your standard bulbs are 12 volts and draw 2 amps then each bulbs resistance value is 6 ohms (12 ÷ 2 = 6).
Or if they were 12 volt and drew 3.7 amps of current the resistance value of each would be 3.24 ohms (12 ÷ 3.7 = 3.24 (ohms)).
So, if you can use Ohms Law to figure out the resistance value of your standard bulbs you can use Ohms Law to figure out the resistance of the new LED bulbs. You then simply take the standard bulb resistance value and subtract from that the resistance value of the new LEDs, and the resulting number will be the value of resistance that you need to add to each LED bulb for them to operate properly.
=8^)
voltage ÷ current = resistance
For example, if your standard bulbs are 12 volts and draw 2 amps then each bulbs resistance value is 6 ohms (12 ÷ 2 = 6).
Or if they were 12 volt and drew 3.7 amps of current the resistance value of each would be 3.24 ohms (12 ÷ 3.7 = 3.24 (ohms)).
So, if you can use Ohms Law to figure out the resistance value of your standard bulbs you can use Ohms Law to figure out the resistance of the new LED bulbs. You then simply take the standard bulb resistance value and subtract from that the resistance value of the new LEDs, and the resulting number will be the value of resistance that you need to add to each LED bulb for them to operate properly.
=8^)
Where I = amps (2) and E = voltage (12) and P = wattage (?)
P=I*E or ( 2*12 = 24 ), so, using your numbers, the wattage is 24 for 1 bulb.
That means the equalizer (resistor) needs to be rated > 24 watts. Not exactly a typical resistor.
Autozone carries them.
Last edited by cHarley; 02-10-2013 at 06:29 AM.
Trending Topics
#8
Join Date: Oct 2012
Location: In the foothills of southwestern NC - US of A
Posts: 1,358
Likes: 0
Received 22 Likes
on
19 Posts
Now you need the rest of the formula: P=IE
Where I = amps (2) and E = voltage (12) and P = wattage (?)
P=I*E or ( 2*12 = 24 ), so, using your numbers, the wattage is 24 for 1 bulb.
That means the equalizer (resistor) needs to be rated > 24 watts. Not exactly a typical resistor.
Autozone carries them.
Where I = amps (2) and E = voltage (12) and P = wattage (?)
P=I*E or ( 2*12 = 24 ), so, using your numbers, the wattage is 24 for 1 bulb.
That means the equalizer (resistor) needs to be rated > 24 watts. Not exactly a typical resistor.
Autozone carries them.
=8^)
#9
I was really just pointing out for those that don't know any better, that your typical Radio Shack 1/4 or 1/2 watt resistor, is NOT going to cut it.
.