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Engine Mechanical TopicsDiscussion for motor builds, cams, head work, stripped bolts and other engine related issues. The good and the bad. If it goes round and around or up and down, post it here.
I have a 1983 Shovelhead Big Bore. The cylinders are 3-5/8", 0.30 over. The book says that I have a 4.25" stroke stock. The previous owner told me that it has a stroker kit. I'm assuming 1/4" but I'll check after I get the jugs back on. I'm calculating 97.6 CI (96.8 without the 030) stock and 103.3 CI stroked. Am I getting this right? That seems a little bigger than I expected.
Stock the stroke was 4 1/4 the bore was 3 1/2 (3.4975) = 81.6 cu in
4 1/4 stroke x 3 5/8 bore = 88 cu in
4 3/4 stroke x 3 5/8 bore = 97.8
If you look in the the timing hole there will be a S&S number if there are S&S wheels in there
Eastcoast Jim
Last edited by Eastcoast Jim; Jan 27, 2017 at 03:45 PM.
Stock the stroke was 4 1/4 the bore was 3 1/2 (3.4975) = 81.6 cu in
4 1/4 stroke x 3 5/8 bore = 88 cu in
4 3/4 stroke x 3 5/8 bore = 97.8
If you look in the the timing hole there will be a S&S number if there are S&S wheels in there
Eastcoast Jim
My numbers are quite different. Can someone explain why it's not just a simple cylindrical volume calculation?
Check Gordon's post - you probably did some bad math
Pi X r2 X stroke X 2 cylinders
a 74 " motor is 3 7/16 bore x 4" stroke
a factory 80" shovel is 3 1/2 bore x4 1/4 stroke
add 3 5/8 bore cyl = 88 "
Did you check the timing hole for S&S wheels? - Eastcoast Jim
This is a little embarrassing. I was just using a geometric calculator in AutoCAD instead of actually doing math. The numbers looked reasonable so I didn't notice that I was looking at surface area of a cylinder instead of the volume. That's what I get for being lazy.
Now I get:
3-5/8" bore +0.030 / 4.25" stroke = 89.18 CID (87.73 without the 030 over)
If it's 1/4" stroker:
94.43 CID
If it's 1/2" stroker:
99.68 CID
Thanks for helping me figure out that I'm not as smart as I thought I was.
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