Headlight Aiming?
Tourer
Joined: Dec 2008
Posts: 279
Likes: 0
From: Middle River, MD
Got a laser level in the toolbox? If not, sight along the top of a normal carpenter's level. Top edge of the beam should be no higher than the top of the headlight. A few inches lower than that would be ideal. High beam should he nearly horizontal.
Thread Starter
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Ultimate HDF Member
Joined: Mar 2008
Posts: 7,604
Likes: 38
From: Landrum, SC , elevation 986'
For one of my mods all I did was lengthen the OEM bucket.(see last post) I just wanted to get the light adjusted to as close as possible to save a bit of time thats all.
Once I get the motor back together I'll fine tune the light adjustment and put a mark on the wall where I park just to make sure it stays that way.
There is a chome hood and a custom bag that goes on the OEM mount also.
Once I get the motor back together I'll fine tune the light adjustment and put a mark on the wall where I park just to make sure it stays that way.
There is a chome hood and a custom bag that goes on the OEM mount also.
Cruiser
Joined: May 2006
Posts: 143
Likes: 0
From:
OhioSkully is right except that the 16.79 inches is the distance down from the headlight at 12 feet distance. The height above the floor is the difference between 35 inches and 16.79 inches. This is 18.21 inches. Make it 18 and a quarter inches and call it good.
Road Master
Joined: Jan 2008
Posts: 1,073
Likes: 6
I plugged it into a right triangle calculator and iam not saying this is right but i came up with 16.79 inchs from the floor.
With the 35 inch at 25 ft the angle at the floor was 6.65 deg that is what i used to come up with 12ft from wall at a 6.65 deg angle from floor and a 90deg at wall gives you 16.79 inchs from the floor and guessing that would be right as you cut the 35 almost in half and the 25 almost in half should be dam close.
With the 35 inch at 25 ft the angle at the floor was 6.65 deg that is what i used to come up with 12ft from wall at a 6.65 deg angle from floor and a 90deg at wall gives you 16.79 inchs from the floor and guessing that would be right as you cut the 35 almost in half and the 25 almost in half should be dam close.
The trigonometry is easy, we just need to know the height of the headlight that's supposed to shine 35" off the ground at 25'.
Now, you can do some trigonometry or you can use the formula I just derived for you.
X = 0.52 * H + 16.8
where
X = height of center of light spot at wall 12' away
H = height of center of headlight
(sorry, I couldn't resist the excuse to do some math - it's the enginerd in me.)
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