Andrews "b"
Seasoned HDF Member
Joined: Nov 2006
Posts: 12,878
Likes: 5,449
From: la la land jerzey
the compression trapped is called - static
and lobe separation comes into play in this as well as lobe center - low center numbers is the low engine speed grunt
a bbc chevy race engine with a 108 cam center will blow the tires off trying to leave the line but a 110 wont
but the 108 out a corner racing will blast off the corner and down the straight out in front of a 110 even though the 110 is faster up hi in the RPMs
and lobe separation comes into play in this as well as lobe center - low center numbers is the low engine speed grunt
a bbc chevy race engine with a 108 cam center will blow the tires off trying to leave the line but a 110 wont
but the 108 out a corner racing will blast off the corner and down the straight out in front of a 110 even though the 110 is faster up hi in the RPMs
Seasoned HDF Member
Joined: Mar 2010
Posts: 21,116
Likes: 7,638
From: Poolville
We're pretty much talkin stock cubes here not some over stroked Shovel... I'm sure your compression (static) is way the hell up there @59*.. Don't confuse people...
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Road Master
Joined: Apr 2012
Posts: 979
Likes: 38
From: new orleans,la
can I make a suggestion? visit leinwebers cam selection site
-- http://www.leinewebercams.com/PG4_SH...4wfall2016.pdf -- look at the top -- see where it says .020? and .053??
he checks his duration @ .020 every other cam maker uses .053 -- so when you see a closing of 59 its not 59 as your thinking --
maybe YOUR confused but most of us know the difference -- the L3S is for stock 74's and stock 80's --
-- http://www.leinewebercams.com/PG4_SH...4wfall2016.pdf -- look at the top -- see where it says .020? and .053??
he checks his duration @ .020 every other cam maker uses .053 -- so when you see a closing of 59 its not 59 as your thinking --
maybe YOUR confused but most of us know the difference -- the L3S is for stock 74's and stock 80's --
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Road Master
Joined: Apr 2012
Posts: 979
Likes: 38
From: new orleans,la
like your evo in the pic --( nice bike by the way ) I have a 1984 evo-- fxrs its 10:5:1 just a 80" - I use this cam
E5S - IN .544 40/54 - 274 duration --
EX .544 68/26 -- .274 -- THE actual duration @ .53 is 242 -- Mr. Jims cam timing is what confusing to most till you understand -- ask johnjzjz -- twisted - they will show you what is ment ..
that E5S is really killer in a stock 80" evo I used the TP roller rockers
E5S - IN .544 40/54 - 274 duration --
EX .544 68/26 -- .274 -- THE actual duration @ .53 is 242 -- Mr. Jims cam timing is what confusing to most till you understand -- ask johnjzjz -- twisted - they will show you what is ment ..
that E5S is really killer in a stock 80" evo I used the TP roller rockers
Seasoned HDF Member
Joined: Mar 2010
Posts: 21,116
Likes: 7,638
From: Poolville
Even though the duration is stated at .020" the timing of the cam doesn't change...? Does it...? I mean the intake valve still starts to open@35* and close@59*... Doesn't it?
Thanks on the Evo comment.. I have a lot in that thing...
Thanks on the Evo comment.. I have a lot in that thing...
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Road Master
Joined: Apr 2012
Posts: 979
Likes: 38
From: new orleans,la
this is my 84 fxrs - not as Purdy as yours but it does have a s*it load of hp -
the cams from leinweber are measured @ 20 going up the lobe not 53 so yeah it changes the numbers where it begins to lift and close
Advanced
Joined: Jun 2025
Posts: 90
Likes: 9
Kinetic energy (KE) = ˝ mv2 we know this from our intro physics classes where m is mass and v is velocity.
E = qV gives us the energy of a charged particle where q is the charge and V is the potential difference in Volts in which the particle falls and gains energy.
This engine uses Xenon atoms that have a mass m = 2.2 x 10-25 kg and a charge of the all-familiar q of 1.6 x 10-19 coulombs, a constant that we all know and have indelibly printed into our engineering brains.
We know that 1/2mv2(Kinetic energy) = q (charge) x V (Voltage)
So, now lets calculate the speed of a Xenon atom in km/hr, assuming that the voltage grid V of the ion engine is 1,300 V:
Let KE = E and we now solve for v:
Kinetic energy = charge x Voltage
v2 = 2qV/m = 2(1.6 x 10-19coulombs)(1,300V)/(2.2 x 10-25kg) = 2.0 x 109
Taking the square root of 2.0 x 109 gives us v = 44.2 km/sec or 159,000 km/hr WOW! Thats fast.
E = qV gives us the energy of a charged particle where q is the charge and V is the potential difference in Volts in which the particle falls and gains energy.
This engine uses Xenon atoms that have a mass m = 2.2 x 10-25 kg and a charge of the all-familiar q of 1.6 x 10-19 coulombs, a constant that we all know and have indelibly printed into our engineering brains.
We know that 1/2mv2(Kinetic energy) = q (charge) x V (Voltage)
So, now lets calculate the speed of a Xenon atom in km/hr, assuming that the voltage grid V of the ion engine is 1,300 V:
Let KE = E and we now solve for v:
Kinetic energy = charge x Voltage
v2 = 2qV/m = 2(1.6 x 10-19coulombs)(1,300V)/(2.2 x 10-25kg) = 2.0 x 109
Taking the square root of 2.0 x 109 gives us v = 44.2 km/sec or 159,000 km/hr WOW! Thats fast.
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Stellar HDF Member
Joined: May 2018
Posts: 2,171
Likes: 435
From: australia
first evo ?
